The enthalpy of reaction for the reaction

2H2(g)+O2(g)2H2O(l) is rH=-572 kJ mol-1

What will be standard enthalpy of formation of H2O(l)?


Given that,
2H2(g)+O2(g)2H2O(l), rH=?
This can be obtained by dividing the given authority by 2.
Therefore, rH(H2O)=-572 kJ mol-12=-286 kJ mol-1