Ncert Exercises & Solutions

5.2 A vessel of 120 mL capacity contains a certain amount of gas at 35 °C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 mL at 35 °C. What would be its pressure?

Given,

Initial pressure, p₁ = 1.2 bar

Initial volume, V₁ = 120 mL

Final volume, V₂ = 180 mL
Since the temperature remains constant, the final pressure (p₂) can be calculated using Boyle’s law.

According to Boyle’s law,

$p_{1} V_{1} = p_{2} V_{2}$
$\Rightarrow p_{2} = \frac{p_{1} V_{1}}{V_{2}}$
$= \frac{1.2 \times 120}{180} b a r$
$= 0.8 b a r$

Therefore, the pressure would be 0.8 bar.

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