Ncert Exercises & Solutions

2.6 Find the energy of each of the photons which

(i) correspond to light of frequency 3×1015 Hz.

(ii) have a wavelength of 0.50 Å.

(i) Energy (E) of a photon is given by the expression,
E = hv
Where, h = Planck’s constant = 6.626 × $10^{- 34}$ Js
ν = frequency of light = 3 × $10^{15}$ Hz
Substituting the values in the given expression of E:
E = (6.626 × $10^{- 34}$ ) (3 × $10^{15}$ )
E = 1.988 × $10^{- 18}$ J

(ii) Energy (E) of a photon having wavelength (λ) is given by the expression,
$E = \frac{hc}{λ}$
h = Planck’s constant = 6.626 × $10^{- 34}$ Js
c = velocity of light in vacuum = 3 × $10^{8}$ m/s
Substituting the values in the given expression of E:

$E = \frac{(6.626 x 10^{- 34}) (3 x 10^{8})}{0.50 x 10^{- 10}} = 3.976 x 10^{- 15} J$
$∴ E = 3.98 x 10^{- 15 J}$

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