Ncert Exercises & Solutions

2.46 Nitrogen laser produces radiation at a wavelength of 337.1 nm. If the number of photons emitted is 5.6 × 1024, calculate the power of this laser.

Power of laser = Energy with which it emits photons
Power = E = $\frac{Nhc}{λ}$

Where,

N = number of photons emitted
h = Planck’s constant
c = velocity of radiation
λ = wavelength of radiation
Substituting the values in the given expression of Energy (E):

$E = \frac{(5.6 x 10^{24}) (6.626 x 10^{- 34} Js) (3 x 10^{8} m / s)}{(337.1 x 10^{- 9} m)}$
$= 0.3302 x 10^{7} J$
$= 3.33 x 10^{6} J$

Hence, the power of the laser is 3.33 × $10^{6}$ J.

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