Ncert Exercises & Solutions

2.60 The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 × 105 ms–1. If the hockey ball of mass 0.1 kg is moving with this velocity, calcualte the wavelength associated with this velocity.

According to de Broglie’s expression,

λ = \frac{h}{mv}

Substituting the values in the expression,

λ = \frac{6.626 x 10^{- 34} Js}{(0.1 kg) (4.37 x 10^{5} m / s)}

λ = 1.516 x 10^{- 38} m

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