Ncert Exercises & Solutions

45.4 L of dinitrogen reacted with 22.7 L of dioxygen and 45.4 L of nitrous oxide was formed. THe reaction is given below

$2 N_{2} (g) + O_{2} (g) \to 2 N_{2} O (g)$

Which law is being obeyed in this experiment? Write the statement of the law?

For the reaction,

\underset{\frac{45.4}{22.7} = 2}{\underset{2 V}{2 N_{2} (g)}} + \underset{\frac{22.7}{22.7} = 1}{\underset{1 V}{O_{2} (g)}} \to \underset{\frac{45.4}{22.7} = 2}{\underset{2 V}{2 N_{2} O (g)}}

Hence, the ratio between the volumes of the reactants and the product in the given question is simple i.e., 2 : 1 : 2. It proves the Gay-Lussac's law of gaseous volumes.

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