Ncert Exercises & Solutions

1.22 If the speed of light is 3.0 × 108 m s–1, calculate the distance covered by light in 2.00 ns.

According to the question:

Time is taken to cover the distance = 2.00 ns
= 2.00 × $10^{- 9}$ s

Speed of light = 3.0 × 108 m/s

Distance traveled by light in 2.00 ns
= Speed of light × Time taken
= (3.0 × 108 m/s) (2.00 × $10^{- 9}$ s)
= 6.00 × $10^{- 1}$ m
= 0.600 m