Ncert Exercises & Solutions

1.10 In three moles of ethane (C2H6), calculate the following:

(i) Number of moles of carbon atoms.

(ii) Number of moles of hydrogen atoms.

(iii) Number of molecules of ethane.

(i) 1 mole of $C_{2} H_{6}$ contains 2 moles of carbon atoms.
Number of moles of carbon atoms in 3 moles of $C_{2} H_{6}$
= 2 × 3 = 6

(ii) 1 mole of $C_{2} H_{6}$ contains 6 moles of hydrogen atoms.
Number of moles of carbon atoms in 3 moles of $C_{2} H_{6}$
= 3 × 6 = 18

(iii) 1 mole of $C_{2} H_{6}$ contains 6.023 × 10²³ molecules of ethane.
Number of molecules in 3 moles of $C_{2} H_{6}$
$= 3 \times 6.023 \times 10^{23} = 18.069 \times 10^{23}$

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