Ncert Exercises & Solutions

1.9 Calculate the atomic mass (average) of chlorine using the following data:

	% Natural Abundance	Molar Mass
35Cl	75.77	34.9689
37Cl	24.23	36.9659

NEETprep answer:

The average atomic mass of chlorine

$= [(Fractional abundance)]$
$of {}_{35}{Cl} (Molar mass)$
$of {}_{35}{Cl} + (Fractional)$
$abundance$
$of {}_{37}{Cl} (Molar mass)$
$of {}_{37}{Cl}$
$= [\{(\frac{75.77}{100}) (34.9689 u)\} + \{(\frac{24.23}{100}) (36.9659 u)\}]$

= 26.4959 + 8.9568
= 35.4527 u
$∴$ The average atomic mass of chlorine = 35.4527 u

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