Ncert Exercises & Solutions

1.5 Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molars aqueous solution. The molar mass of sodium acetate is 82.0245 g mol^–1.

0.375 M aqueous solution of sodium acetate

≡ 1000 mL of solution containing 0.375 moles of sodium acetate
Number of moles of sodium acetate in 500 mL

$= \frac{0.375}{1000} \times 500$
$= 0.1857 mole$

The molar mass of sodium acetate = 82.0245 g ${mol}^{- 1}$ (Given)
Required mass of sodium acetate = (82.0245 g ${mol}^{- 1}$ ) (0.1875 mole)
= 15.38 g

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