Ncert Exercises & Solutions

33. Calculate the solid angle subtended by the periphery of an area of 1 ${cm}^{2}$ at a point situated symmetrically at a distance of 5 cm from the area.

Hint:

Area = Solid angle \times R^{2}

Step 1: Find the solid angle.

\begin{array}{l} We know that solid angle Ω = \frac{Area}{(Distance)^{2}} \\ = \frac{1 {cm}^{2}}{(5 cm)^{2}} = \frac{1}{25} = 4 \times 10^{- 2} steradian \\ (∵ Area = 1 {cm}^{2}, distance = 5 cm) \end{array}

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