A vehicle travels half the distance \(\mathrm{L} \) with speed \(\mathrm{v_1}\) and the other half with speed \(\mathrm{v_2},\) then its average speed is:
1. v1+v22

2. 2v1+v2v1+v2

3. 2v1v2v1+v2

4. L(v1+v2)v1v2

Hint: The average speed is defined as the total distance divided by the total time.

Step 1: Find the time taken by the vehicle in two cases.

Time is taken to travel the first half distance \(t_1=\frac{1/2}{v_1}=\frac{1}{2v_1}\)
Time is taken to travel second half  distance  \(t_2=\frac{1}{2v_2}\)
 
Total time \(t_1+t_2\) = \(\frac{1}{2v_1}+\frac{1}{2v_2}\) = \(\frac{1}{2}[\frac{1}{v_1}+\frac{1}{v_2}]\)


Step 2: Find the average speed.

We know that, 
\(V_{avg}\) = Average velocity \(\) \(\frac{total~distance}{total~ time}\)  
\(\frac{2v_1v_2}{v_1+v_2}\)

Hence, option (3) is the correct answer.