Q. 24 A woman throws an object of mass 500 g with a speed of 25 m/s.
(a) What is the impulse imparted to the object?
(b) If the object hits a wall and rebounds with half the original speed,
what is the change in momentum of the object?


Hint: Impulse = Change in momentum.
Step 1: Find impulse in the first part

Mass of the object (m) = 500g = 05 kg
Speed of the object (v) 25 my's

(a) Impulse imparted to the object = change in momentum

=mvmu=m(vu)=0.5(250)=12.5Ns

Step 2: Find the change in momentum in the second part

(b) Velocity of the object after rebounding

            =252m/s         v=12.5m/s ∴  Change in momentum =m(vv)                                               =0.5(12.525)=18.75Ns