Ncert Exercises & Solutions

If an average person jogs, he produces \(14.5 \times10^3\) cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming \(1\) kg requires \(580 \times10^3\) cal for evaporation) is:
1. \(0.25\) kg
2. \(0.50\) kg
3. \(0.025\) kg
4. \(0.20\) kg

1. Hint: Use the law of conservation of energy.

Step 1: Find the amount of sweat evaporated.

Amount of sweat evaporated / minute = \frac{Sweat produced / minute}{Number of calories required for evaporation / kg}

= \frac{Amount of heat produced per minute in jogging}{Latent heat (in cal / kg)}

= \frac{14.5 \times 10^{3}}{580 \times 10^{3}} = \frac{14.5}{580} = 0.025 kg

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