Ncert Exercises & Solutions

A tuning fork A, marked 512 Hz, produces 5 beats per second, when sounded with another unmarked tuning fork B. If B is loaded with wax the number of beats is again 5 per second. What is the frequency of the tuning fork B when not loaded?

Hint: The frequency of fork B decreases when it is loaded with wax.

Step 1: Find the probable frequencies of fork B.

Frequency of tuning fork A = 512 Hz

Probable frequency of tuning fork B = 517 Hz or 507 Hz

Step 2: Find the actual frequency of fork B.

When B is loaded, its frequency reduces.

If it is 517 Hz, it might be reduced to 507 Hz, giving again a beat of 5 Hz.

If it is 507 Hz, the reduction will always increase the beat frequency, Hence,

v_{B}

= 517 Hz

Note: For the production of beats frequencies of the two tuning forks must be nearly equal i.e, slight difference in frequencies

NEET Information

courses

Company

Botany Questions

Chemistry Questions

Physics Questions

Zoology Questions