Ncert Exercises & Solutions

Assume that there is no repulsive force between the electrons in an atom but the force between positive and negative charges is given by Coulomb's law as usual. Under such circumstances, calculate the ground state energy of He-atom.

Hint: Use Bohr's model of atom.

Step 1: Find the energy of He-atom in the ground state.

For He-nucleus with charge 2e and electrons of charge -e, the energy level in ground state is:

- E_{n} = Z^{2} \frac{- 13.6 eV}{n^{2}} = 2^{2} \frac{- 13.6 eV}{1^{2}} = - 54.4 eV

Thus, the ground state will have two electrons each of energy E and the total ground state energy would be

- (4 \times 13.6) eV = - 54.4 eV .

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