Question 11.12: Calculate the
(a) momentum, and
(b) de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.
Step 2: Find the momentum of the electron.
The momentum of each accelerated electron is given as:
p= mv = 9.1 x 10-31 x 4.44 x 106 = 4.04 x
Step: Find the De Broglie wavelength of an electron.
De Broglie wavelength of an electron accelerating through a potential V is given by the relation:
Therefore, the de Broglie wavelength of each electron is 0.1639 nm.