A ray of light incident at an angle θ on a refracting face of a prism emerges from the other face normally. If the angle of the prism is 5° and the prism is made of a material of refractive index 1.5, the angle of incidence is:

1. 7.5°
2. 5°
3. 15°
4. 2.5°

(1) Hint: The angle of refraction at the second surface is equal to zero.

Step 1: Find the angle of deviation.

Since deviation δ= (μ-1) A= (1.5-1)×5°= 2.5°

Step 2: Find the angle of incident.

By geometry, the angle of refraction by the first surface is 5°.

But δ=θ-r, so, we have, 2.5°=θ - 5°, on solving θ= 7.5°.