Ncert Exercises & Solutions

You are given a $2 μF$ parallel plate capacitor. How would you establish an instantaneous displacement current of 1 mA in the space between its plates?

Hint: The displacement current depends on the rate of change potential across the capacitor.

Step 1: Use the equation of the displacement current.

Given, capacitance of capacitor, C = 2 μF,

Displancement current, I_{d} = 1 mA

Charge, q = CV

I_{d} dt = CdV

or I_{d} = C \frac{dV}{dt}

Step 2 : Find the potential difference .

1 \times 10^{- 3} = 2 \times 10^{- 6} \times \frac{dV}{dt}

or \frac{dV}{dt} = \frac{1}{2} \times 10^{3} = 500 V / s

So, by applying a varying potential difference of 500 V/s, we would produce a displacement current of desired value.

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