Ncert Exercises & Solutions

Question 7.3 :

A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in the circuit.

As given :

The inductor connected to the AC supply has an inductance of L = 44 m H = 44 × 10 ^{– 3} H

The magnitude of the source voltage V is 220 V

The frequency of the source is ν = 50 Hz

The angular frequency of the source is given by ω = 2 π ν

The Inductive reactance X _L can be calculated as follows:

ω _L = 2 π ν L = 2π × 50 × 44 × 10 ^{– 3} Ω

To find the RMS value of current we use the following relation:

$\bar{a} I = \frac{V}{X_{L}} = \frac{220}{2 π \times 50 \times 44 \times 10^{\circ}} = 15.92 A$

Therefore, the RMS value of the current in the network is 15.92 A.