Ncert Exercises & Solutions

A permanent magnet in the shape of a thin cylinder of length 10 cm has M = $10^{6}$ A/m. Calculate the magnetization current $I_{M}$ .

Hint: Apply the concept of the intensity of magnetisation.

Step 1: Given, M (intensity of magnetisation) =

10^{6}

A/m.
l(length) = 10 cm = 10 x

10^{- 2}

m = 0.1 m
and

I_{M}

= magnetisation current
Step 2:

\begin{array}{ll} We know that & M = \frac{I_{M}}{l} \\ \Rightarrow & I_{M} = M \times l \\ = 10^{6} \times 0 .1 = 10^{5} A \end{array}