Ncert Exercises & Solutions

Find the current in the wire for the configuration shown in the figure. Wire PQ has negligible resistance. B, the magnetic field is coming out of the paper. $θ$ is a fixed angle made by PQ travelling smoothly over two conducting parallel wires separated by a distance d.

Hint: The induced emf depends on the change in magnetic flux.

Step 1: The induced emf is given by;

ε = |- \frac{dϕ}{dt}| = |- \frac{d (BA)}{dt}| = B \frac{dA}{dt} = Bd \frac{dx}{dt} = vdB

Step 2: This induced emf make the flow of current in the closed circuit of resistance R.

I = \frac{dvB}{R}

and is independent of q.

NEET Information

courses

Company

Botany Questions

Chemistry Questions

Physics Questions

Zoology Questions