Ncert Exercises & Solutions

Q 10. A jet plane is traveling towards the west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10^–4 T and the dip angle is 30°.

Speed of the plane with which it is moving, v = 1800 km/h = 500 m/s

The wingspan of the jet, l = 25 m

Magnetic field strength by the earth, null

Dip angle, $°$

The vertical component of Earth’s magnetic field,

$\begin{array}{l} B v = B \sin δ \\ = 5 \times 10^{- 4} \sin 30^{\circ} \\ = 2.5 \times 10^{- 4} T \end{array}$

The voltage difference between the ends of the wing can be calculated as:

\begin{array}{l} e = (B v) \times 1 \times v \\ = 2.5 \times 10^{- 4} \times 25 \times 500 \\ = 3.125 V \end{array}

Hence, the voltage difference developed between the ends of the wings is 3.125 V.

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