Ncert Exercises & Solutions

5.5 A closely wound solenoid of 800 turns and area of cross-section
2.5 × 10–4 m2 carries a current of 3.0 A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?

Number of turns in the solenoid, n = 800,

Area of cross-section,

A = 2.5 \times 10^{- 4} m^{2}

Current in the solenoid, I = 3.0 A

A current-carrying solenoid behaves as a bar magnet because a magnetic field develops along its axis, i.e., along its length.

The magnetic moment associated wth the given current-carrying solenoid is calculated as: M = n I A

= 800 \times 3 \times 3.5 \times 10^{- 4} = 0.6 J T^{- 1}

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