5.5 A closely wound solenoid of 800 turns and area of cross-section 
2.5 × 10
–4 m2 carries a current of 3.0 A. Explain the sense in which the solenoid acts like a bar magnet. What is its associated magnetic moment?

Number of turns in the solenoid, n = 800,
Area of cross-section, A=2.5×10-4m2
Current in the solenoid, I = 3.0 A
A current-carrying solenoid behaves as a bar magnet because a magnetic field develops along its axis, i.e., along its length.
The magnetic moment associated wth the given current-carrying solenoid is calculated as: M = n I A
=800×3×3.5×10-4=0.6 J T-1