Ncert Exercises & Solutions

Q 2.8) In a parallel plate capacitor with air between the plates, each plate has an area of 6 x 10^-3 m ² and and the distance between the plates is 3 mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100 V supply, what is the charge on each plate of the
capacitor?

Given,

The area of plate of the capacitor, A = 6 x 10^-3 m²

Distances between the plates, d = 3mm = 3 x 10^-3m

Voltage supplied, V = 100v

Capacitance of a parallel plate capacitor is given by, $C = \frac{ϵ \times A}{d}$

Here,

ε = permittivity of free space = 8.854 × 10^-12 N^-1 m ^-2 C^-2

$C = \frac{8.854 \times 10^{- 12} \times 6 \times 10^{- 3}}{3 \times 10^{- 3}} = 17.81 \times 10^{- 12} F = 17.71 p F$

Therefore, each plate of the capacitor is having a charge of

q = VC = 100 × 17.81 x 10^-12 C = 1.771 x 10^-9C

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