Ncert Exercises & Solutions

10.17 A U-shaped wire is dipped in a soap solution and removed. The thin soap film formed between the wire and the light slider supports a weight of 1.5 × 10^–2 N (which includes the small weight of the slider). The length of the slider is 30 cm. What is the surface tension of the film?

Given,

The weight supported by the soap film, W = 1.5 × 10^–2 N

Length of the slider, l = 30 cm = 0.3 m

A soap film has two free surfaces.

Total length in consideration = 2l = 2 × 0.3 = 0.6 m

Surface tension, $S = \frac{Weight}{Total length}$ $= \frac{1.5 \times 10^{- 2}}{0.6} = 2.5 \times 10^{- 2} N / m$

Therefore, the surface tension of the film is 2.5 × 10^–2 N m^–1.

NEET Information

courses

Company

Botany Questions

Chemistry Questions

Physics Questions

Zoology Questions