Ncert Exercises & Solutions

9.20 Two strips of metal are riveted together at their ends by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 107 Pa? Assume that each rivet is to carry one-quarter of the load.

$Radius of each rivet, r = \frac{d}{2} = 3.0 \times 10^{- 3} m$

Maximum shearing stress on each rivet = 6.9 × 10 $^{7}$ Pa

Maximum stress = $\frac{Maximum load or force}{Area}$

Maximum force on each rivet = Maximum stress on each rivet × Area

= 6.9 × $10^{7} \times π \times {(r)}^{2}$

$= 6.9 \times 10^{7} \times π \times {(3.0 \times 10^{- 3})}^{2}$

= 1949.94 N

Maximum tension on the riveted strip = 4 × 1949.94 = 7799.76 N

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