Q. 21 A door is hinged at one end and is free to rotate about a vertical axis (figure). Does its weight cause any torque about this axis? Give reason for your answer.
Consider the diagram, where the weight of the door acts along the negative y-axis.
A force can produce torque only along a direction normal to itself as . So, when the door is in the xy-plane, the torque produced by gravity can only be along ± z-direction never about an axis passing through y-direction.
Hence, the weight will not produce any torque about the x-axis.
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