The potential energy function for a particle executing linear SHM is given by V(x)=12kx2 where k is the force constant of the oscillator (Fig). For k = 0.5 N/m, the graph of V(x) versus x is shown in the figure. A particle of total energy E turns back when it reaches x=±m. If V and K indicate the PE and KE, respectively of the particle at x=+m, then which of the following is correct?



1. V=0, K=E
2. V=E, K=0
3. V<E, K=0
4. V=0, K,E

(b) Hint: Apply the concept of conservation of energy.

Step 1: Find the potential energy and the kinetic energy at the extreme position.

Total energy is E = PE+ KE

When particle is at x = m i.e., at extreme position, returns back. Hence. at x = m; v = 0, K.E. = 0

From Eq. (I) E=PE+0=PE=V(m)=12kxm2