Length of the pendulum, l = 1.5 m

Mass of the bob = m

Energy dissipated = 5%

According to the law of conservation of energy, the total energy of the system remains constant.

At the horizontal position:

Potential energy of the bob, $U_p$ = mgl

The kinetic energy of the bob, ${\mathrm{E}}_{\mathrm{k}}$ = 0

Total energy = mgl … (i)

At the lowermost point (mean position):

The potential energy of the bob, $U_{\mathrm{p}}\text{'}$ = 0

The kinetic energy of the bob, ${\mathrm{E}}_{\mathrm{k}} = \frac{1}{2}{\mathrm{mv}}^2$

Total energy${\mathrm{E}}_T = \frac{1}{2}{\mathrm{mv}}^2$ … (ii)

As the bob moves from the horizontal position to the lowermost point, 5% of its energy gets dissipated.

The total energy at the lowermost point is equal to 95% of the total energy at the horizontal point, i.e.,

$\frac{1}{2}{\mathrm{mv}}^2 = \frac{95}{100} \times \mathrm{mgl}$
$\Rightarrow \mathrm{v} = \sqrt{\frac{2 \times 55 \times 1.5 \times 9.8}{100}}$

       = 5.28 m/s