Q.36 Consider a one-dimensional motion of a particle with total energy E. There are four regions A, B, C, and D in which the relation between potential energy V, kinetic energy (K), and total energy E is as given below

Region A : V > E    Region B : V < E
Region C : K < E    Region D : V > E

State with reason in each case whether a particle can be found in the given region or not.

Hint: Use total energy, E = PE + KE.
Step 1: Interpreat about the differente regions by using E = PE + KE.

We know that

Total energy, E = PE + KE

    E = V + K                             ...(I)

For region A Given, V > E. From Eq. (i)

K = E - V

as V > E  E - V < 0

Hence, K < 0, this is not possible.

For region B Given, V < E  E — V > 0
This is possible because total energy can be greater than PE

For region C Given, K > E  K - E > 0
from Eq. (I) PE = V = E - K < 0
This is possible: because PE can be negative.

For region D Given, V > K
This is possible because for a system PE (V) may be greater than KE (K).