Q. 8.  In an experiment, DNA is treated with the compound which tends to place itself amongst the stacks of nitrogenous base pairs. As a result of this, the distance between two consecutive base increases. From 0.34-0.44 nm calculate the length of DNA double helix (which has 2×109 bp) in the presence of saturating of this compound.


The length of DNA double helix = 2×109×0.44×10-9/bp.