If the mean free path of atoms is doubled then the pressure of the gas will become:
1. \(P/4\)           
2. \(P/2\)           
3. \(P/8\)           
4. \(P\)

The mean free path of molecules of a gas, (radius r) is inversely proportional to :
1. r³
2. r²
3. r
4. \(\sqrt{r}\)

The mean free path of gas molecules depends on (d = molecular diameter)

1. $\mathrm{d}$                                         

2. ${\mathrm{d}}^2$

3. ${\mathrm{d}}^{-2}$                                   

4. ${\mathrm{d}}^{-1}$

If the pressure in a closed vessel is reduced by drawing out some gas, the mean free path of the molecules:

Assertion: At a particular temperature, the value of the mean free path increases with a decrease in pressure.

Reason: All the gas molecules at a particular temperature possess the same speed.