- 1(current)
Q. No.A square current-carrying loop is suspended in a uniform magnetic field acting in the plane of the loop. If the force on one arm of the loop is \( \overrightarrow{F}\), what will be the net force on the remaining three arms of the loop?
| 1. | \(3 \overrightarrow{F}\) | 2. | \(- \overrightarrow{F}\) |
| 3. | \(-3 \overrightarrow{F}\) | 4. | \( \overrightarrow{F}\) |
Subtopic: Â Current Carrying Loop: Force & Torque |
 83%
Level 1: 80%+
AIPMT - 2010
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A closed-loop \(PQRS\) carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments \(PS,\) \(SR,\) and \(RQ\) are \(F_1, F_2~\text{and}~F_3\) respectively, and are in the plane of the paper and along the directions shown, then which of the following forces acts on the segment \(QP?\)
1. \(F_{3} - F_{1} - F_{2}\)
2. \(\sqrt{\left(F_{3} - F_{1}\right)^{2} + F_{2}^{2}}\)
3. \(\sqrt{\left(F_{3} - F_{1}\right)^{2} - F_{2}^{2}}\)
4. \(F_{3} - F_{1} + F_{2}\)
Subtopic: Â Current Carrying Loop: Force & Torque |
 79%
Level 2: 60%+
AIPMT - 2008
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A circular loop with a radius of \(20~\text{cm}\) is placed in a uniform magnetic field \(\mathrm B=2~\text{T}\) in the \(XY\) plane as shown in the figure. If the loop carries a current of \(i = 1~\text{A},\) then the magnitude of torque acting on the loop will be:
1. \(0.25~\text{N-m}\)
2. \(5.2~\text{N-m}\)
3. \(2.5~\text{N-m}\)
4. \(0.52~\text{N-m}\)
1. \(0.25~\text{N-m}\)
2. \(5.2~\text{N-m}\)
3. \(2.5~\text{N-m}\)
4. \(0.52~\text{N-m}\)
Subtopic: Â Current Carrying Loop: Force & Torque |
 72%
Level 2: 60%+
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- 1(current)
Q. No.
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