Q. No.The percentage increase in the speed of transverse waves produced in a stretched string if the tension is increased by \(4\%\), will be:
1. \(1\%\)
2. \(2\%\)
3. \(3\%\)
4. \(4\%\)
A steel wire \(0.72~\text{m}\) long has a mass of \(5\times10^{-3}~\text{kg}\). If the wire is under tension of \(60~\text{N}\), the speed of transverse waves on the wire will be:
1. \(85~\text{m/s}\)
2. \(83~\text{m/s}\)
3. \(93~\text{m/s}\)
4. \(100~\text{m/s}\)
| 1. | \({y}=0.2 \sin \left[2 \pi\left(6{t}+\frac{x}{60}\right)\right]\) |
| 2. | \({y}=0.2 \sin \left[ \pi\left(6{t}+\frac{x}{60}\right)\right]\) |
| 3. | \({y}=0.2 \sin \left[2 \pi\left(6{t}-\frac{x}{60}\right)\right]\) |
| 4. | \(y=0.2 \sin \left[ \pi\left(6{t}-\frac{x}{60}\right)\right]\) |
The phase difference between two waves, represented by
\(y_1= 10^{-6}\sin \left\{100t+\left(\frac{x}{50}\right) +0.5\right\}~\text{m}\)
\(y_2= 10^{-6}\cos \left\{100t+\left(\frac{x}{50}\right) \right\}~\text{m}\)
where \(x\) is expressed in metres and \(t\) is expressed in seconds, is approximate:
1. \(2.07~\text{radians}\)
2. \(0.5~\text{radians}\)
3. \(1.5~\text{radians}\)
4. \(1.07~\text{radians}\)
| 1. | \(50~\text{cm}\) | 2. | \(60~\text{cm}\) |
| 3. | \(25~\text{cm}\) | 4. | \(20~\text{cm}\) |
1. \(3:2\)
2. \(2:3\)
3. \(9:4\)
4. \(4:9\)
1. \(1.21~\mathring{A}\)
2. \(2.42~\mathring{A}\)
3. \(0.605~\mathring{A}\)
4. \(4.84~\mathring{A}\)
| 1. | \(3\) | 2. | \(360\) |
| 3. | \(180\) | 4. | \(60\) |
1. \(\frac{1}{n}= \frac{1}{n_1}+\frac{1}{n_2}+\frac{1}{n_3}\)
2. \(n= n_1\times n_2\times n_3\)
3. \(n= n_1+ n_2+ n_3\)
4. \(n= \frac{n_1+ n_2+ n_3}{3}\)
Two stationary sources exist, each emitting waves of wavelength λ. If an observer moves from one source to the other with velocity u, then the number of beats heard by him is equal to:
1.
2.
3.
4.
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