The molar solubility of CaF2 (Ksp=5.3 × 10-11) in 0.1 M solution of NaF will be:

1. 5.3 × 10-11 mol L-1

2. 5.3 × 10-8 mol L-1

3. 5.3 × 10-9 mol L-1

4. 5.3 × 10-10 mol L-1

Subtopic:  Solubility Product |
 65%
From NCERT
NEET - 2019
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When 10 ml of 0.1 M acetic acid (pKa=5.0) is titrated against 10 ml of 0.1 M
ammonia solution (pKb=5.0), the pH at equivalence point will be:

1. 9.0 2. 6.0
3. 5.0 4. 7.0
Subtopic:  Salt Hydrolysis & Titration |
 77%
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For the reaction 2NOCl(g)⇔2NO(g)+Cl2(g), KC at 427°C is \(3\times 10^{-6} \ mol\ L^{-1}\). The value of Kp will be :

1. 1.72×10-4

2. 7.50×105

3. 2.50×10-5

4. 2.50×10-4

Subtopic:  Kp, Kc & Factors Affecting them |
 83%
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The standard reduction potential for Cu2+/Cu is 0.34 V.
The reduction potential at pH =14 for the above couple given KspCuOH2=1×10-19 is :

1.  -0.22 V

2.  +0.22 V

3.  -0.34 V

4.  +0.34 V

Subtopic:  Solubility Product |
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The pH of a 0.01 M NaOH (aq) solution will be:

1. 7.01

2. 2

3. 12

4. 9

Subtopic:  pH calculation |
 80%
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The oxoacid that has the highest Ka value is: t

1 HClO3

2 HBrO3

3 HlO3

4 All have equal Ka

Subtopic:  Acids & Bases - Definitions & Classification |
 50%
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Litmus is not affected by hydracids when they are

1. In contact with water

2. Dry

3. Fused with each other                 

4. Mixed together and dissolved in water

Subtopic:  Acids & Bases - Definitions & Classification |
 73%
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For the following reaction, 
 H2(g)+I2(g)2HI(g) at 250°C,

The effect on the state of equilibrium on doubling the volume of the system will be:

1. Shift to the reactant side 2. Shift to the product side 
3. No effect on the state of equilibrium 4. Liquefaction of HI

Subtopic:  Le Chatelier's principle |
 82%
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Which of the following cannot act as a buffer? 
1. NaH2PO4 + H3PO4
2. NH4OH + NH4CI
3. NaOH + CH3COONa
4. Both (1) & (3)

Subtopic:  Buffer |
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If the pH of 0.1 M NaCN solution is 11, then the percentage hydrolysis will be:

1. 0.1%

2. 1%

3. 0.01%

4. 10%

Subtopic:  Salt Hydrolysis & Titration |
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