- 1(current)
Q. No.The quantum numbers of four electrons are given below:
I. \(n\)=4; \(l\)=2; \(m_l\)=-2; and s=-\(\frac1{2}\)
II. \(n\)=3; \(l\)=2; \(m_l\)=1; and s=+\(\frac1{2}\)
III. \(n\)=4; \(l\)=1; \(m_l\)=0; and s=+\(\frac1{2}\)
IV. \(n\)=3; \(l\)=1; \(m_l\)=-1; and s=+\(\frac1{2}\)
The correct decreasing order of energy of these electrons is:
1. IV>II>III>I
2. I>III>II>IV
3. III>I>II>IV
4. I>II>III>IV
I. \(n\)=4; \(l\)=2; \(m_l\)=-2; and s=-\(\frac1{2}\)
II. \(n\)=3; \(l\)=2; \(m_l\)=1; and s=+\(\frac1{2}\)
III. \(n\)=4; \(l\)=1; \(m_l\)=0; and s=+\(\frac1{2}\)
IV. \(n\)=3; \(l\)=1; \(m_l\)=-1; and s=+\(\frac1{2}\)
The correct decreasing order of energy of these electrons is:
1. IV>II>III>I
2. I>III>II>IV
3. III>I>II>IV
4. I>II>III>IV
Subtopic: Â Pauli's Exclusion Principle & Hund's Rule |Â AUFBAU Principle |
 77%
Level 2: 60%+
NEET - 2024
Hints
Which one of the following electrons in the ground state will have least amount of energy?
| 1. | An electron in hydrogen atom. |
| 2. | An electron in 2p orbital of carbon atom. |
| 3. | The electron of copper atom present in 4s orbital. |
| 4. | The outermost electron in sodium atom. |
Subtopic: Â AUFBAU Principle |
 68%
Level 2: 60%+
NEET - 2022
Hints
4d, 5p, 5f and 6p orbitals are arranged in the order of decreasing energy. The correct option is:
| 1. | 5f > 6p > 4d > 5p | 2. | 5f > 6p > 5p > 4d |
| 3. | 6p > 5f > 5p > 4d | 4. | 6p > 5f > 4d > 5p |
Subtopic: Â AUFBAU Principle |
 69%
Level 2: 60%+
NEET - 2019
Hints
- 1(current)
Q. No.
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