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Q. No.The quantum numbers of four electrons are given below:
I. \(n\)=4; \(l\)=2; \(m_l\)=-2; and s=-\(\frac1{2}\)
II. \(n\)=3; \(l\)=2; \(m_l\)=1; and s=+\(\frac1{2}\)
III. \(n\)=4; \(l\)=1; \(m_l\)=0; and s=+\(\frac1{2}\)
IV. \(n\)=3; \(l\)=1; \(m_l\)=-1; and s=+\(\frac1{2}\)
The correct decreasing order of energy of these electrons is:
1. IV>II>III>I
2. I>III>II>IV
3. III>I>II>IV
4. I>II>III>IV
I. \(n\)=4; \(l\)=2; \(m_l\)=-2; and s=-\(\frac1{2}\)
II. \(n\)=3; \(l\)=2; \(m_l\)=1; and s=+\(\frac1{2}\)
III. \(n\)=4; \(l\)=1; \(m_l\)=0; and s=+\(\frac1{2}\)
IV. \(n\)=3; \(l\)=1; \(m_l\)=-1; and s=+\(\frac1{2}\)
The correct decreasing order of energy of these electrons is:
1. IV>II>III>I
2. I>III>II>IV
3. III>I>II>IV
4. I>II>III>IV
Subtopic: Â Pauli's Exclusion Principle & Hund's Rule |Â AUFBAU Principle |
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NEET - 2024
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