Galileo’s law of odd numbers: “The distances traversed, during equal intervals of time, by a body falling from rest, stand to one another in the ratio:

1.  as the odd numbers beginning with unity.

2.  as the even numbers beginning with unity.

3.  as the square of odd numbers beginning with unity.

4.  as the square of even numbers beginning with unity.

 

A train is moving in south with a speed of 90 ${\mathrm{kmh}}^{-1}$. The velocity of ground with respect to the train is:

1.  0 ${\mathrm{ms}}^{-1}$

2.  -25 ${\mathrm{ms}}^{-1}$

3.  25 ${\mathrm{ms}}^{-1}$

4.  -40 ${\mathrm{ms}}^{-1}$

Two parallel rail tracks run north-south. Train A moves north with a speed of 54 ${\mathrm{kmh}}^{-1}$, and train B moves south with a speed of 90 ${\mathrm{kmh}}^{-1}$. The magnitude of the velocity of B with respect to A is:

1.  40 ${\mathrm{ms}}^{-1}$

2.  0 ${\mathrm{ms}}^{-1}$

3.  25 ${\mathrm{ms}}^{-1}$

4.  15 ${\mathrm{ms}}^{-1}$

A train is moving in the north direction with a speed of \(54\) ${\mathrm{kmh}}^{-1}$. The velocity of a monkey running on the roof of the train against its motion (with a velocity of \(18\) ${\mathrm{kmh}}^{-1}$ with respect to the train) as observed by a man standing on the ground is:
1. \(40\) ms^-1
2. \(0\)
3. \(-5\) ms^-1
4. \(10\) ms^-1

The position of an object moving along the x-axis is given by, \(x=a+bt^2\)  where \(a=8.5\) m, \(b=2.5\) ms^-2, and \(t\) is measured in seconds. Its velocity at \(t=2.0\) s will be:
1. \(13\) m/s
2. \(17\) m/s
3. \(10\) m/s
4. \(0\) 

The position-time graph for a free-falling object is:
1. a parabolic curve
2. a straight line
3. a circular curve
4. an elliptical curve

You can measure your reaction time by a simple experiment. Take a ruler and ask your friend to drop it vertically through the gap between your thumb and forefinger (figure shown below). After you catch it if the distance d travelled by the ruler is \(21.0\) cm, your reaction time is:

1. \(0.2\) s
2. \(0.4\) s
3. \(0\) 
4. \(0.1\) s

When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity \(\mathrm{v_0}\) and the braking capacity, or deceleration, \(-a\) that is caused by the braking. Expression for stopping distance of a vehicle in terms of \(\mathrm{v_0}\) and \(a\) is:
1. \(\frac{\mathrm{v_o}^2}{2a}\)
2. \(\frac{\mathrm{v_o}}{2a}\)
3. \(\frac{\mathrm{v_o}^2}{a}\)
4. \(\frac{2a}{\mathrm{v_o}^2}\)

A ball is thrown vertically upwards with a velocity of \(20\) m/s from the top of a multistorey building. The height of the point from where the ball is thrown is \(25.0\) m from the ground. How long will it be before the ball hits the ground? (Take \(g=10\) ms^-2.)
1. \(3\) s
2. \(2\) s
3. \(5\) s
4. \(20\) s

A ball is thrown vertically upwards with a velocity of \(20\) m/s from the top of a multistorey building. The height of the point from where the ball is thrown is \(25.0\) m from the ground. How high will the ball rise from the point of throw? (Take \(g=10\) m/s²)