The equation of an SHM is given as y=3sinωt + 4cosωt where y is in centimeters. The amplitude of the SHM will be?
1. | 3 cm | 2. | 3.5 cm |
3. | 4 cm | 4. | 5 cm |
A particle executing simple harmonic motion of amplitude \(5~\text{cm}\) has a maximum speed of \(31.4~\text{cm/s}.\) The frequency of its oscillation will be:
1. \(1~\text{Hz}\)
2. \(3~\text{Hz}\)
3. \(2~\text{Hz}\)
4. \(4~\text{Hz}\)
Two simple harmonic motions of angular frequency 100 rad s -1 and 1000 rad have the same displacement amplitude. The ratio of their maximum acceleration will be:
1. 1:10
2. 1:102
3. 1:103
4. 1:104
If a particle is executing SHM, with an amplitude A, the distance moved and the displacement of the body in a time equal to its time period are, respectively:
1. | 2A, A | 2. | 4A, 0 |
3. | A, A | 4. | 0, 2A |
A body performs simple harmonic motion about x=0 with an amplitude a and a time period T. The speed of the body at will be:
1.
2.
3.
4.
The amplitude of a simple harmonic oscillator is \(A\) and speed at the mean position is \(v_0\) .The speed of the oscillator at the position \(x={A \over \sqrt{3}}\) will be:
1. | \(2v_0 \over \sqrt{3}\) | 2. | \(\sqrt{2}v_0 \over 3\) |
3. | \({2 \over 3}v_0\) | 4. | \(\sqrt{2}v_0 \over \sqrt{3}\) |
A particle executes SHM with a time period of 4 s. The time taken by the particle to go directly from its mean position to half of its amplitude will be:
1. s
2. 1 s
3. s
4. 2 s
A point performs simple harmonic oscillation of period \(\mathrm{T}\) and the equation of motion is given by; \(x=a \sin (\omega t+\pi / 6)\). After the elapse of what fraction of the time period, the velocity of the point will be equal to half of its maximum velocity?
1. \( \frac{T}{8} \)
2. \( \frac{T}{6} \)
3. \(\frac{T}{3} \)
4. \( \frac{T}{12}\)
A particle executes linear SHM between \(x=A.\) The time taken to go from \(0\) to \(A/2\) is and to go from \(A/2\) to \(A\) is , then:
1. | 2. | ||
3. | 4. |
The amplitude and the time period in an S.H.M. are 0.5 cm and 0.4 sec respectively. If the initial phase is radian, then the equation of S.H.M. will be:
1.
2.
3.
4.