The energy equivalent of one atomic mass unit is:

1. $1.6\times {10}^{-19}$ $J$ 

2. $6.02\times {10}^{23}$ $J$

3. 931 MeV 

4. 9.31 MeV

A nuclear reaction along with the masses of the particle taking part in it is as follows;

$A + B \to C + D + Q MeV$
$1.002 1.004 1.001 1.003$
$amu amu amu amu$

The energy Q liberated in the reaction is:

1. 1.234 MeV

2. 0.931 MeV

3. 0.465 MeV

4. 1.862 MeV

Determine the energy released in the process:

${}_{1}H_2+{}_{1}H_2\to {}_{2}H{e}^4+Q$

Given: M $\left({}_{1}H_2\right)$= 2.01471 amu

            M$\left({}_{2}H{e}^4\right)$= 4.00388 amu

1. 3.79 MeV
2.13.79 MeV
3. 0.79 MeV 
4. 23.79 MeV

If an electron and a positron annihilate, then the energy released is:

1. $3.2\times {10}^{-13}$ $\mathrm{J}$       

2. $1.6\times {10}^{-13}$ $\mathrm{J}$

3. $4.8\times {10}^{-13}$ $\mathrm{J}$           

4. $6.4\times {10}^{-13}$ $\mathrm{J}$

The energy required in \(\mathrm{MeV} / \mathrm{c}^2\) to separate \({ }_8^{16} \mathrm{O}\) into its constituents is:
(Given mass defect for \({ }_8^{16} \mathrm{O}=0.13691 \mathrm{u}\))
1. \(127.5\)
2. \(120.0\)
3. \(222.0\)
4. \(119.0\)

A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in the fusion reaction is 0.02866 u. The energy liberated per nucleon is: (Given 1 u = 931 MeV)

The energy equivalent of \(0.5\) g of a substance is:
1. \(4.5\times10^{13}\) J
2. \(1.5\times10^{13}\) J
3. \(0.5\times10^{13}\) J
4. \(4.5\times10^{16}\) J

If a proton and anti-proton come close to each other and annihilate, how much energy will be released?

Calculate the Q-value of the nuclear reaction:
\(2~{ }_{6}^{12} \mathrm{C}\rightarrow{ }_{10}^{20} \mathrm{Ne}+{ }_2^4 \mathrm{He}\)
The following data are given:
\(m({ }_{6}^{12} \mathrm{C})=12.000000~\text{u}\)
\(m({ }_{10}^{20} \mathrm{Ne})=19.992439~\text{u}\)
\(m({ }_{2}^{4} \mathrm{He})=4.002603~\text{u}\)
1. \(3.16~\text{MeV}\)
2. \(5.25~\text{MeV}\)
3. \(3.91~\text{MeV}\)
4. \(4.65~\text{MeV}\)

The rest energy of an electron is: