Determine the energy released in the process:

${}_{1}H_2+{}_{1}H_2\to {}_{2}H{e}^4+Q$

Given: M $\left({}_{1}H_2\right)$= 2.01471 amu

            M$\left({}_{2}H{e}^4\right)$= 4.00388 amu

1. 3.79 MeV
2.13.79 MeV
3. 0.79 MeV 
4. 23.79 MeV

When ${}_{3}L{i}^7$ nuclei are bombarded by protons, and the resultant nuclei are ${}_{4}B{e}^8$, the emitted particles will be:

If $\frac{N}{Z}$ ratio in a nucleus is smaller than the required value for stability, then:

What is the respective number of $\alpha$ and $\beta$-particles emitted in the following radioactive decay?
\(X^{200}_{90}\rightarrow Y^{168}_{80}\)

If a proton and anti-proton come close to each other and annihilate, how much energy will be released?

Fusion reaction takes place at a higher temperature because:

Which of the following pairs of nuclei are isotones?

1. ${}_{34}{}^{74}\mathrm{Se},$ ${}_{31}{}^{71}\mathrm{Ca}$          

2. ${}_{42}{}^{92}\mathrm{Mo},$ ${}_{40}{}^{92}\mathrm{Zr}$

3. ${}_{38}{}^{81}\mathrm{Sr},$ ${}_{38}{}^{86}\mathrm{Sr}$             

4. ${}_{20}{}^{40}\mathrm{Ca},$ ${}_{16}{}^{32}\mathrm{S}$

If in nuclear reactor using U²³⁵ as fuel, the power output is 4.8 MW, the number of fissions per second is:
(Energy released per fission of U²³⁵ = 200 MeV watts, 1 eV = 1.6 X 10^–19 J)

1. 1.5×10¹⁷           

2. 3×10¹⁹           

3. 1.5×10²⁵           

4. 3×10²⁵

=Calculate the Q-value of the nuclear reaction:
\(2~{ }_{6}^{12} \mathrm{C}\rightarrow{ }_{10}^{20} \mathrm{Ne}+{ }_2^4 \mathrm{He}\)
The following data are given:
\(m({ }_{6}^{12} \mathrm{C})=12.000000~\text{u}\)
\(m({ }_{10}^{20} \mathrm{Ne})=19.992439~\text{u}\)
\(m({ }_{2}^{4} \mathrm{He})=4.002603~\text{u}\)
1. \(3.16~\text{MeV}\)
2. \(5.25~\text{MeV}\)
3. \(3.91~\text{MeV}\)
4. \(4.65~\text{MeV}\)