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At 100 °C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be:
| 1. | 100 oC | 2. | 102 oC |
| 3. | 103 oC | 4. | 101 oC |
Subtopic: Relative Lowering of Vapour Pressure | Elevation of Boiling Point |
59%
Level 3: 35%-60%
NEET - 2016
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If 8 g of a non-electrolyte solute is dissolved in 114 g of n-octane to reduce its vapor pressure to 80 %, the molar mass (in g mol–1) of the solute is:
[Molar mass of n-octane is 114 g mol–1]
| 1. | 40 | 2. | 60 |
| 3. | 80 | 4. | 20 |
Subtopic: Relative Lowering of Vapour Pressure |
62%
Level 2: 60%+
NEET - 2020
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