A and B are the inputs for the given logic gate. The output Y will be:

1. 2.
3. 4.
Subtopic:  Logic gates |
 75%
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The two inputs (\(A\)) and (\(B\)) of a logic circuit are shown along with the output (\(Y\)) as functions of time. The 'highs' represent logic \(1\) and the 'lows' represents logic \(0\). The correct truth table for this circuit is: 

 
1.
\(A\) \(B\) \(Y\)
\(0\) \(0\) \(0\)
\(0\) \(1\) \(0\)
\(1\) \(0\) \(1\)
\(1\) \(1\) \(0\)
2.
\(A\) \(B\) \(Y\)
\(0\) \(0\) \(0\)
\(0\) \(1\) \(1\)
\(1\) \(0\) \(0\)
\(1\) \(1\) \(0\)
3.
\(A\) \(B\) \(Y\)
\(0\) \(0\) \(1\)
\(0\) \(1\) \(0\)
\(1\) \(0\) \(0\)
\(1\) \(1\) \(1\)
4.
\(A\) \(B\) \(Y\)
\(0\) \(0\) \(0\)
\(0\) \(1\) \(1\)
\(1\) \(0\) \(1\)
\(1\) \(1\) \(0\)
Subtopic:  Logic gates |
 79%
From NCERT
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