Q. No.Consider the given reaction and products:
The correct statement about the given chemical reaction is :
1. -NH2 group is ortho and para directive, so product (B) is not possible.
2. Reaction is possible and compound (B) will be the major product.
3. The reaction will form sulphonated product instead of nitration.
4. Reaction is possible and compound (A) will be major product.
Subtopic: Mechanism |
84%
Level 1: 80%+
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In the following reaction, the reason why meta-nitro product also formed is:
1. Low temperature
2. –NH2 group is highly meta-directive
3. Formation of anilinium ion
4. –NO2 substitution always takes place at meta-position
Subtopic: Mechanism |
76%
Level 2: 60%+
JEE
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Consider the following sequence of reaction.
Which of the following option contains the correct structure?
Which of the following option contains the correct structure?
| 1. | A is  |
2. | B is  |
| 3. | C is  |
4. | D is  |
Subtopic: Mechanism |
81%
Level 1: 80%+
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Consider the given reaction:
The correct order of the set of reagents for the above conversion is:
The correct order of the set of reagents for the above conversion is:
| 1. | \(\mathrm{Br}_2 \mid \mathrm{FeBr}_3, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}\) |
| 2. | \(\mathrm{H}_2 \mathrm{SO}_4, \mathrm{Ac}_2 \mathrm{O}, \mathrm{Br}_2, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}\) |
| 3. | \(\mathrm{Ac}_2 \mathrm{O}, \mathrm{Br}_2, \mathrm{H}_2 \mathrm{O}(\Delta), \mathrm{NaOH}\) |
| 4. | \(\mathrm{Ac}_2 \mathrm{O}, \mathrm{H}_2 \mathrm{SO}_4, \mathrm{Br}_2, \mathrm{NaOH}\) |
Subtopic: Mechanism |
Level 4: Below 35%
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Subtopic: Mechanism |
Level 4: Below 35%
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Subtopic: Mechanism |
70%
Level 2: 60%+
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Given below are two statements:
| Assertion (A): | Experimental reaction of \(CH_3Cl \) with aniline and anhydrous \(AlCl_3\) does not give o and p-methylaniline |
| Reason (R): | The \(-NH_2 \) group of aniline becomes deactivating because of salt formation with anhydrous \(AlCl_3 \) and hence yields m-methyl aniline as the product. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A) |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A) |
| 3. | (A) is True but (R) is False |
| 4. | (A) is False but (R) is True |
Subtopic: Mechanism |
Level 4: Below 35%
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What is the maximum amount of acetanilide (report to the nearest integer) formed when acetic anhydride in excess is treated with \(18~\text{gm}\) of aniline?
| 1. | 27 | 2. | 24 |
| 3. | 26 | 4. | 22 |
Subtopic: Mechanism |
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Level 3: 35%-60%
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Decarboxylation of all six possible forms of diaminobenzoic acid \(\mathrm{C_6H_3(NH_2)_2COOH}\) yields three products A, B and C. Three acids give a product ‘A’, two acids give a product ‘B’, and one acid gives a product ‘C’. The melting point of product ‘C’ is:
1. \(\mathrm{63^\circ C}\)
2. \(\mathrm{90^\circ C}\)
3. \(\mathrm{104^\circ C}\)
4. \(\mathrm{142^\circ C}\)
1. \(\mathrm{63^\circ C}\)
2. \(\mathrm{90^\circ C}\)
3. \(\mathrm{104^\circ C}\)
4. \(\mathrm{142^\circ C}\)
Subtopic: Mechanism |
74%
Level 2: 60%+
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| Statement I | Grignard reagent (R–MgX) reacts with CO₂ followed by acidification to form a carboxylic acid (R–COOH). This on heating with NH₃ forms an amide (R–CONH₂), which on treatment with NaOCl gives a primary amine (R–NH₂). The amine on reaction with CHCl₃/NaOH forms an isocyanide (R-NC). |
| Statement II | Isocyanide (R-NC) on hydrolysis gives Carboxylic acid (RCOOH). |
Choose the correct option:
| 1. | Statement-I and Statement-II both are correct |
| 2. | Statement-I is incorrect Statement-II is correct |
| 3. | Statement-I is correct Statement-II is incorrect |
| 4. | Statement-I and Statement-II both incorrect |
Subtopic: Amines - Preparation & Properties | Cyanides & Isocyanides | Mechanism |
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