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Q. No.What is the reason behind the color of KMnO4?
1. d-d transition
2. Charge transfer spectra
3. Both (1) and (2)
4. Polarisation of anion
Subtopic: Chemistry of Mn and Cr Compounds |
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When acidified \(KMnO_4 \) reacts with oxalic acid gives a manganese product. Find the magnetic moment (spin only) of \(Mn\) in this product:
1. 2
2. 6
3. 0
4. 4
1. 2
2. 6
3. 0
4. 4
Subtopic: Chemistry of Mn and Cr Compounds |
65%
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White ppt of AgCl dissolves in \(NH_4OH\) due to the formation of:
1. AgOH
2. \(Ag_2O\)
3. \([Ag(NH_3)_2]Cl \)
4. \([Ag(NH_3)_4]Cl \)
1. AgOH
2. \(Ag_2O\)
3. \([Ag(NH_3)_2]Cl \)
4. \([Ag(NH_3)_4]Cl \)
Subtopic: d-Block Elements- Properties & Uses |
71%
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Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
| Assertion (A): | Ce3+ ion and Yb+3 ion are colourless. |
| Reason (R): | Ce3+ ion and Yb+3 ion cannot show f-f transition |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
Subtopic: f-Block Elements- Properties & Uses |
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| Assertion (A): | Colour of KMnO4 became light pink when oxalic acid is added to its solution in an acidic medium. |
| Reason (R): | KMnO4 is a strong oxidising agent. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
Subtopic: Chemistry of Mn and Cr Compounds |
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X, Y, and Z in the following reactions are:
\(\begin{aligned} \mathrm{MnO}_4^{-}+\mathrm{e}^{-} & \longrightarrow \mathrm{X} \\ \mathrm{MnO}_4^{-}+4 \mathrm{H}^{+}+3 \mathrm{e}^{-} & \longrightarrow \mathrm{Y} \\ \mathrm{MnO}_4{ }^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} & \longrightarrow \mathrm{Z} \end{aligned} \)
1. \(X= Mn^{2+} ,~~Y=MnO_2,~~Z= MnO^{2-}_4 \)
2. \(X= MnO_{2} ,~~Y=Mn^{2+},~~Z= MnO^{2-}_4 \)
3. \(X= MnO_{2} ,~~Y=MnO^{2-}_4,~~Z= Mn^{2+} \)
4. \(X= MnO^{2-}_4 ,~~Y=MnO_2,~~Z= Mn^{2+} \)
\(\begin{aligned} \mathrm{MnO}_4^{-}+\mathrm{e}^{-} & \longrightarrow \mathrm{X} \\ \mathrm{MnO}_4^{-}+4 \mathrm{H}^{+}+3 \mathrm{e}^{-} & \longrightarrow \mathrm{Y} \\ \mathrm{MnO}_4{ }^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} & \longrightarrow \mathrm{Z} \end{aligned} \)
1. \(X= Mn^{2+} ,~~Y=MnO_2,~~Z= MnO^{2-}_4 \)
2. \(X= MnO_{2} ,~~Y=Mn^{2+},~~Z= MnO^{2-}_4 \)
3. \(X= MnO_{2} ,~~Y=MnO^{2-}_4,~~Z= Mn^{2+} \)
4. \(X= MnO^{2-}_4 ,~~Y=MnO_2,~~Z= Mn^{2+} \)
Subtopic: d-Block Elements- Properties & Uses |
80%
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Subtopic: d-Block Elements- Properties & Uses |
62%
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When \(V_2O_5\) reacts with base and acid, X and Y are formed respectively. X and Y are:
1. \(X = VO^{3-}_4 ,~~~Y = VO^{+} _2\)
2. \(X = VO^{3-}_4 ,~~~Y = VO^{+}_4 \)
3. \(X = VO^{+}_4 ,~~~Y = VO^{3-}_4 \)
4. \(X = VO^{2+} ,~~~Y = V_2O_{3} \)
1. \(X = VO^{3-}_4 ,~~~Y = VO^{+} _2\)
2. \(X = VO^{3-}_4 ,~~~Y = VO^{+}_4 \)
3. \(X = VO^{+}_4 ,~~~Y = VO^{3-}_4 \)
4. \(X = VO^{2+} ,~~~Y = V_2O_{3} \)
Subtopic: d-Block Elements- Properties & Uses |
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The pair in the actinide series that can have the highest oxidation state is:
1. Np, Pu
2. U, Am
3. U, Cm
4. Am, Cm
1. Np, Pu
2. U, Am
3. U, Cm
4. Am, Cm
Subtopic: d-Block Elements- Properties & Uses |
78%
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Correct statement for the given reaction is:
\(\mathrm{Cr}_2 \mathrm{O}_7{ }^{2-}(a q)+\mathrm{SO}_3{ }^{2-}(a q) \rightarrow \mathrm{Cr}^{3+}(a q)+\mathrm{SO}_4{ }^{2-}(a q)\)
1. Generally \(SO_4^{2-}\) is not a reducing agent.
2. \(Cr^{3+} \) can be further reduced in this reaction.
3. Oxidation by \(SO_3^{2-} \) gives \(Cr^{3+} \)
4. In \(Cr_2O^{2-}_7 \) oxidation state of Cr is not +6.
\(\mathrm{Cr}_2 \mathrm{O}_7{ }^{2-}(a q)+\mathrm{SO}_3{ }^{2-}(a q) \rightarrow \mathrm{Cr}^{3+}(a q)+\mathrm{SO}_4{ }^{2-}(a q)\)
1. Generally \(SO_4^{2-}\) is not a reducing agent.
2. \(Cr^{3+} \) can be further reduced in this reaction.
3. Oxidation by \(SO_3^{2-} \) gives \(Cr^{3+} \)
4. In \(Cr_2O^{2-}_7 \) oxidation state of Cr is not +6.
Subtopic: d-Block Elements- Properties & Uses |
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