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Q. No.20 ml of solution of 0.1M acetic acid is titrated with 0.1 M NaOH solution. After the addition of 16 ml NaOH the pH of the solution is:
(pKa = 4.75)
1. 5.05
2. 4.15
3. 5.35
4. 4.75
(pKa = 4.75)
1. 5.05
2. 4.15
3. 5.35
4. 4.75
Subtopic: pH calculation |
From NCERT
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The pH of 10-6 M CH3COOH will be:
(ka of CH3COOH = 1.8 \(\times\) 10-5 & log 4.24 =0.63)
1. 5.37
2. 7.0
3. Slightly more than 6
4. 6.95
Subtopic: pH calculation |
From NCERT
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Arrange the following solutions in the decreasing order of pOH:
1. (A) > (C) > (D) > (B)
2. (A) > (D) > (C) > (B)
3. (B) > (C) > (D) > (A)
4. (B) > (D) > (C) > (A)
| (A) | \(0.01 \mathrm{M} \ \mathrm{HCl} \) |
| (B) | \( 0.01 \mathrm{M}\ \mathrm{NaOH} \) |
| (C) | \( 0.01 \mathrm{M} \ \mathrm{CH}_3 \mathrm{COONa}\) |
| (D) | \(0.01 \mathrm{M} \ \mathrm{NaCl} \) |
2. (A) > (D) > (C) > (B)
3. (B) > (C) > (D) > (A)
4. (B) > (D) > (C) > (A)
Subtopic: pH calculation |
From NCERT
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