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Q. No.Which of the following contains the highest number of helium atoms?
1. 4 u of helium
2. 4 g of helium
3. 2.27 L of helium at STP
4. 4 mol of helium
1. 4 u of helium
2. 4 g of helium
3. 2.27 L of helium at STP
4. 4 mol of helium
Subtopic: Moles, Atoms & Electrons |
79%
From NCERT
NEET - 2024
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1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to :
1. 250 mg
2. Zero mg
3. 200 mg
4. 750 mg
1. 250 mg
2. Zero mg
3. 200 mg
4. 750 mg
Subtopic: Millimole/Equivalent Concept |
56%
NEET - 2024
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A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is :
( Given atomic mass of A=64; B=40; C=32u)
1. ABC3
2. AB2C2
3. ABC4
4. A2BC2
( Given atomic mass of A=64; B=40; C=32u)
1. ABC3
2. AB2C2
3. ABC4
4. A2BC2
Subtopic: Empirical & Molecular Formula |
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From NCERT
NEET - 2024
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4.74 g of an inorganic compound contains 0.39g of K, 0.27 g Al, 1.92 g of \(\mathrm{SO_4}\) radicals and 2.16 g of water. If molar mass of the compound is \(948 \mathrm{~g} \mathrm{~mol}^{-1},\) the molecular formula of the inorganic compound is:
| 1. | \(\mathrm{KAl}\left(\mathrm{SO}_4\right)_2 \cdot 12 \mathrm{H}_2 \mathrm{O}\) |
| 2. | \(\mathrm{K}_2 \mathrm{Al}_2\left(\mathrm{SO}_4\right)_6 \cdot 12 \mathrm{H}_2 \mathrm{O}\) |
| 3. | \(\mathrm{K}_2 \mathrm{SO}_4 \cdot \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \cdot24 \mathrm{H}_2 \mathrm{O}\) |
| 4. | \(\mathrm{K}_2 \mathrm{SO}_6 \cdot \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \cdot12 \mathrm{H}_2 \mathrm{O}\) |
Subtopic: Empirical & Molecular Formula |
58%
From NCERT
NEET - 2024
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Molar mass of a compound \(\text{(X)}\) whose \(2.6 \mathrm{~mol}\) weighs \(312 \mathrm{~g}\) is:
1. \(312 \mathrm{~g} \mathrm{~mol}^{-1}\)
2. \(120 \mathrm{~g} \mathrm{~mol}^{-1}\)
3. \(60 \mathrm{~g} \mathrm{~mol}^{-1}\)
4. \(811.2 \mathrm{~g} \mathrm{~mol}^{-1}\)
1. \(312 \mathrm{~g} \mathrm{~mol}^{-1}\)
2. \(120 \mathrm{~g} \mathrm{~mol}^{-1}\)
3. \(60 \mathrm{~g} \mathrm{~mol}^{-1}\)
4. \(811.2 \mathrm{~g} \mathrm{~mol}^{-1}\)
Subtopic: Empirical & Molecular Formula |
82%
From NCERT
NEET - 2024
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The mass of CO2 produced by heating 20 g of 20% pure limestone as per the given below equation is:
\(\left[\mathrm{CaCO}_3 \stackrel{1200 \mathrm{~K}}{\longrightarrow} \mathrm{CaO}+\mathrm{CO}_2\right] \)
\(\left[\mathrm{CaCO}_3 \stackrel{1200 \mathrm{~K}}{\longrightarrow} \mathrm{CaO}+\mathrm{CO}_2\right] \)
| 1. | 1.32 g | 2. | 1.12 g |
| 3. | 1.76 g | 4. | 2.64 g |
Subtopic: Equation Based Problem |
72%
From NCERT
NEET - 2023
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Select the correct statements from the following:
Choose the correct answer from the option given below:
| A: | Atoms of all elements are composed of two fundamental particles. |
| B: | The mass of the electron is \(9.10939 \times 10^{-31} \mathrm{~kg} \text {. }\). |
| C: | All the isotopes of a given element show same chemical properties. |
| D: | Protons and electrons are collectively known as nucleons. |
| E: | Dalton's atomic theory regarded the atom as an ultimate particle of matter. |
| 1. | B, C and E only | 2. | A, B and C only |
| 3. | C, D and E only | 4. | A and E only |
Subtopic: Introduction |
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From NCERT
NEET - 2023
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The density of 1 M solution of a compound 'X' is 1.25 g mL–1. The correct option for the molality of solution is:
(Molar mass of compound X = 85 g):
(Molar mass of compound X = 85 g):
| 1. | 0.705 m | 2. | 1.208 m |
| 3. | 1.165 m | 4. | 0.858 m |
Subtopic: Concentration Based Problem |
64%
From NCERT
NEET - 2023
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Calculate the mass of 95% pure CaCO3 that will be required to neutralize 50 mL of 0.5 M HCl solution according to the following reaction.
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
| 1. | 9.50 g | 2. | 1.25 g |
| 3. | 1.32 g | 4. | 3.65 g |
Subtopic: Equation Based Problem |
52%
From NCERT
NEET - 2022
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NEET 2025 - Target Batch
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Match List-I with List-II:
| List-I | List-II | ||
| (a) | 4.48 litres of O2 at STP | (i) | 0.2 moles |
| (b) | 12.022 × 1022 molecules of H2O | (ii) | 12.044 × 1023 molecules |
| (c) | 96 g of O2 | (iii) | 6.4 g |
| (d) | 88 g of CO2 | (iv) | 67.2 litres at STP |
Choose the correct answer from the options given below:
| (a) | (b) | (c) | (d) | |
| 1. | (i) | (iii) | (iv) | (ii) |
| 2. | (iii) | (i) | (iv) | (ii) |
| 3. | (iv) | (i) | (ii) | (iii) |
| 4. | (iii) | (i) | (ii) | (iv) |
Subtopic: Moles, Atoms & Electrons |
From NCERT
NEET - 2022
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NEET 2025 - Target Batch
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