If \(x = 5 \mathrm {sin }\left(\pi t+ {\dfrac {\pi} 3}\right)~\text m\) represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively are:
1. \(5~\text m, 2~\text s\)
2. \(5~\text {cm}, 1~\text s\)
3. \(5~\text m, 1~\text s\)
4. \(5~\text {cm}, 2~\text s\)
Subtopic:  Simple Harmonic Motion |
 72%
From NCERT
NEET - 2024
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The displacement-time \((x\text-t)\) graph of a particle performing simple harmonic motion is shown in the figure. The acceleration of the particle at \(t=2\) s is:
1. \(-\dfrac{\pi^2}{16} ~\text{ms}^{-2}\) 2. \(\dfrac{\pi^2}{8}~ \text{ms}^{-2}\)
3. \(-\dfrac{\pi^2}{8} ~\text{ms}^{-2}\) 4. \(\dfrac{\pi^2}{16} ~\text{ms}^{-2}\)
Subtopic:  Simple Harmonic Motion |
 66%
From NCERT
NEET - 2023
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The phase difference between displacement and acceleration of a particle in a simple harmonic motion is:

1. \(\dfrac{3\pi}{2}\text{rad}\) 2. \(\dfrac{\pi}{2}\text{rad}\)
3. zero 4. \(\pi ~\text{rad}\)
Subtopic:  Simple Harmonic Motion |
 75%
From NCERT
NEET - 2020
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The displacement of a particle executing simple harmonic motion is given by, \(y = A_{0} + A\sin \omega t+ B \cos\omega t.\)
Then the amplitude of its oscillation is given by:
1. \(A + B\) 2. \(A_{0}\) \(+\) \(\sqrt{A^{2} + B^{2}}\)
3. \(\sqrt{A^{2} + B^{2}}\) 4. \(\sqrt{A_{0}^{2}+\left( A + B \right)^{2}}\)
Subtopic:  Simple Harmonic Motion |
 59%
From NCERT
NEET - 2019
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The average velocity of a particle executing SHM in one complete vibration is:
1. zero
2. \(\dfrac{A \omega}{2}\)
3. \(A \omega\)
4. \(\dfrac{A \left(\omega\right)^{2}}{2}\)

Subtopic:  Simple Harmonic Motion |
 73%
From NCERT
NEET - 2019
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The distance covered by a particle undergoing SHM in one time period is: (amplitude = A)

1. zero 2. A
3. 2 A 4. 4 A
Subtopic:  Simple Harmonic Motion |
 76%
From NCERT
NEET - 2019
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