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A uniform ring of mass \(M\) and radius \(R\) has a particle of mass \(m\) placed at its centre, as shown in the figure. The gravitational force exerted by the particle (mass : \(m\)) on the ring (mass : \(M\)) is:
| 1. | proportional to \(\dfrac{Mm}{R^2}\) | 2. | proportional to \(\dfrac{Mm}{R^3}\) |
| 3. | proportional to \(\dfrac{Mm}{R}\) | 4. | zero |
Subtopic: Â Gravitational Field |
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